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August Updates 2 - I made my decision about the next patch + Information revealed.

Tue Aug 15, 2017 11:15 am by Chuck Norris

Before you reply: If you are not happy with anything in this post you are free to provide criticism, but please note two things:

1. Read the Community Manager vs Community section properly and try to address it when you post a reply.

2. Do not make threats to you will leave or insults to me. I am under a lot of preasure and as a leader I have to make tough decisions I can't save everyone and I can't please everyone. If you say stuff like that I will immediately throw your opinion away and cut ties with you in anyway.

This post is going to be tough on me and It might be last post in the staff depending on how you guys handle these two recommendations. (Even if that is the case I will still script for the server of course)

The Community vs the Community manager
As the Community manager and the scripter I represent the vision this server has and I respresent every single person who has ever joined the server. The vision I have is very specific and too long to be brought up in …

[ Full reading ]

Comments: 33

August Updates - Patch 3.7/4.0 & 3.6.2 Sliding??? Information and please read.

Mon Jul 31, 2017 10:00 am by Chuck Norris

Sliding won't work in rel004 apparently.
According to some people sliding doesn't work in rel004, that would mean that updating to this version would probably upset a lot of people. I want to hear from you guys, are you okay with this?


Patch 3.6.2
I am Little confused whether or not I should release patch 3.6.2 or release it together with patch 3.7, to make that patch even bigger. I Think people will be upset that patch 3.6.2 mostly contains improvements and bug fixes, (apart from maybe 4 minor things). What do you guys Think I should do?

Patch 3.7 or 4.0
Same thing here, I can do things with patch 3.7 that would go great with 4.0 and actually change the server a Little. So I am not sure if I should release it as patch 4.0 or 3.7.

Comments: 25

July updates - Patch 3.6.1, questions and the future

Sun Jul 09, 2017 12:40 pm by Chuck Norris

Hey guys just wanted to give you my updates.

Patch 3.6.1
I've made a few content updates for this one, but mostly it is bug fixes and the anti hack system. I have improved the old anti hack system making it harder to be detected if you're not hacking. For example if you are on a vehicle and shooting, and stuff like that, you don't get detected. I've also added prevention for some other hacks that might make playing on the server less fun for the hackers. I can't promise that all types of hacks will be prevented, but the more add I to the system the less hacks work, eventually most of them should be prevented. But it is up to samir ullah, if he can find a way to get around my detections. If he does I'll just keep adding more detections.

There is also some other things that will be added that was missing in patch 3.6, but none of you have noticed it yet and hopefully you will not notice it Before I release patch 3.6.1. When will it be released? I've tested the anti hack system …

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Comments: 36

May Update - Patch 3.6 and just talking.

Sun May 21, 2017 4:24 pm by VK.Angel.OfDeath

Hey guys sorry about patch 3.6 not being released at the start of May. I am bad at keeping my promises, but the truth is: Scripting for the server is a lot of hard work. I work from 8 am to 7 pm on weekdays and usually have a lot to do on the weekends as well. I am scripting the server because I Think it's fun, but I get a lot of stress from working on it sometimes. The server has gotten so big and there is so much new things to script and at the same time improve the old stuff. I know most of the people on the forum don't do minigames like races and other things, but I still want to expand on that as well. The property system is Always something I am proud of and you guys are really going to enjoy the upcoming updated in patch 3.6 for that.

In the summer which starts in about 2-3 weeks for me, I am going to be scripting a lot as long I don't lose all my motivation. Patch 3.6 will be released soon, but I want this patch to be special and therefor I want to get a lot of work …

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Comments: 26

Server Updates April - Patch 3.5.4 and 3.6 + The future.

Sun Apr 09, 2017 10:54 am by VK.Angel.OfDeath

Patch 3.5.4
Patch 3.5.4 will come next weekend. I will include the bug fixes for the racing system and a few other improvements. I was planning on releasing it this weekend, but If I am going to make a new patch at least need to give you guys something, so I will delay it for the next weekend so I can give you a few skins/vehicles as well. Hopefully this is okay by krlozz or anyone else who is having trouble unlocking things from the race system.

Patch 3.6
Patch 3.6 will come out by the end of april or by latest the first week of may. It will include updates to the property system that I came up with by Studying lancer's work and just by thinking about DMers. It will also include more races set in: Custom properties, that's right. It will also include some exciting event stuff and more. Note I have already scripted about 40-50 % of patch 3.6 while I was doing the other patches for you, ain't that some multitasking shit right Razz.

The future
As you guys know the summer is coming up …

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Comments: 19

[Updated] March monthly update - Turbo Glitch, New small patch coming this weekend.

Sat Mar 04, 2017 10:54 am by Chuck Norris

The only way.
Guys I don't want to punish anyone that hasn't done anything. My system for the turbo glitching has one negative and stupid side effect! If you hold shift and then press num6, VC-MP doesn't know that you press num6. It's only freaking shift as well! This means that there is still a way to do the turbo glitch. So angel why can't you create a system for it? Well that would mean that anyone who holds shift or presses shift after they enter first person view would also get caught by the system if I were to prevent people from turbo glitching. So basically there are only two solutions to this.

1. FPV ban, anyone caught abusing the turbo glitch will not be FPV banned which means that you can't use the FPV mode on the server. An alternative would be add number 2 for players who are only FPV banned.

2. If I freeze the player for 100 ms  (which is about a 10th of a sec) after exiting first person view the glitch will be impossible to do. The thing about this is that it will …

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Comments: 30

February updates - Bad news + Patch 3.5 out next weekend + Talking about the future again.

Sat Feb 04, 2017 9:50 am by VK.Angel.OfDeath

Bad news
I've only got a few hours to script each week and unfortunately I have wasted a lot of it on NPCs. I honestly don't have motivation to finish the NPC script, because I want to add so much and have so little time. That means that there will be Little new content for you guys to do. It will mostly just be improvements, there won't be any new minigames, jobs or custom content (custom content doesn't take long to add so I'll probably just do it like 1-2 weeks after patch 3.5). That's definitely a Disappointment to me. Even though I made a lot of improvements you guys been asking for, not adding something big in a patch makes me disappointed. I know most of you guys are just going to do DMing and will probably appreciate the improvements more the new content, but that's how I feel about it at least.

What's important now is that the bugs get fixed and I give the improvements to you guys.


Patch 3.5
I am going to push for patch 3.5 to get out this weekend. My plans today …

[ Full reading ]

Comments: 39

January updates - Talking about new patches

Mon Jan 16, 2017 1:32 pm by VK.Angel.OfDeath

Why there is no release date for the patch at the moment.

1. Not sure if I've made one recently. Well about 3.5, I don't want to release patch 3.5 until it adds something unique to the game. I am working on NPCs. The code for the NPCs is very old and not written very well, but the thing about it is that the code is smart & runs very well, which constantly puts me in a position should I just re-write the code or continue working on it. It kinda gives me a lot of stress because I can't decide what to do.

2. Including that I have to do a lot of testing. I've re-scripted the custom property system so that the build system can be used for other things as well that will come in the future. For you guys the custom property system will be exactly the same, but code wise it's changed a little, which means I have to do some bug tests.

3. NPCs also have to be bug tested.

4. Last weekend was lost to me due to the fact that someone decided it was a good idea to have an exam on a saturday... …

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Comments: 12

Topic(s) Of the Month, (July & August 2016)

Wed Nov 09, 2016 9:27 pm by =KF=Thunder^

Note for this month:Hello Guys, I hereby, Sincerely Apologise towards all of you for being so late with this topic, I intended to post it much earlier than this but I was really busy with other stuff such as studies etc.. also, my laziness got the better of me Razz Therefore, I apologise once again!

Previous Topics of the Month-
http://vkserver.big-forum.net/t4474-topics-of-the-month-may-june-2016, (Just incase you missed them),


Important/must read/must reply topic's
- http://vkserver.big-forum.net/t3201-every-admin-reply-schedule-when-you-play

Decision topic
- No decision topic(s) this month.

News topic


Community updates


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Comments: 21


Math Topic

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Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 6:01 pm

Hello Everybody
Welcome to Math Topic
Here we will post mathematical problems and who solve willl be genius :V
Rules
1- No Spamming [ok Thunder]
2- No Problems that its answers belong to imaginary set of numbers like [divide on zero and sqaure root of negative number]
3- No Stupid answers like [2+2 = 22]
if you answered wrong then there is not any proplem and try again

our First Question [Rate : EASY]

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Find Value of X and how you get the value
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Re: Math Topic

Post by KAKAN on Sun Jan 29, 2017 6:06 pm

3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:06 pm

12 v:

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 6:07 pm

[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:08 pm

[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )

Shit u did it first, vut just v: do 3/6 fisrt

3/6= 2 * 6 = 12 v: easy :p

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 6:09 pm

if you answered it right you should post another problem
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Re: Math Topic

Post by Dark|R|aZoR^ on Sun Jan 29, 2017 6:11 pm

Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people Wink

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 6:13 pm

DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people Wink
3x =24-5
3x = 19
x = 19/3
x=6.3
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:13 pm

A little impossible v: around 6


2/4 = 4/x

V:

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Re: Math Topic

Post by KAKAN on Sun Jan 29, 2017 6:14 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p


Last edited by KAKAN on Sun Jan 29, 2017 6:15 pm; edited 1 time in total
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:15 pm

Zeyad berd u sayinf we shoukd put a new problem and u dont .-.

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Re: Math Topic

Post by KAKAN on Sun Jan 29, 2017 6:15 pm

[You must be registered and logged in to see this link.] wrote:Zeyad berd u sayinf we shoukd put a new problem and u dont .-.
You didn't answer my question Sad
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:18 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Zeyad berd u sayinf we shoukd put a new problem and u dont .-.
You didn't answer my question Sad

Wait im e.e

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 6:20 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Images = {-6 , -3 , -2 , -1 , 2}

My Another Question
if x+y = z-x then z =?
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Re: Math Topic

Post by Vipe[R] on Sun Jan 29, 2017 6:22 pm

IM HERE TO SPAM!

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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:31 pm

X+y+x v:

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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 6:32 pm

X+y+x v:

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Re: Math Topic

Post by 5.J^ on Sun Jan 29, 2017 7:07 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Images = {-6 , -3 , -2 , -1 , 2}

My Another Question
if x+y = z-x then z =?

Z = 2x+y
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Re: Math Topic

Post by Dark|R|aZoR^ on Sun Jan 29, 2017 7:13 pm

[You must be registered and logged in to see this link.] wrote:
DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people Wink
3x =24-5
3x = 19
x = 19/3
x=6.3
Wrong. Re-do your calculations.

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p
KAKAN is perr0. (perr0= pr0 Razz)

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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 7:43 pm

Ah ye 2x xD

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 8:17 pm

DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people Wink
3x+5 = 24
3x = 25-5
3x = 19
x = 19 /3 =6.33333333
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Re: Math Topic

Post by Chuck Norris on Sun Jan 29, 2017 8:32 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 10:04 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v
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Re: Math Topic

Post by Chuck Norris on Sun Jan 29, 2017 10:33 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection  or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John  : Martin :      Sum
   x   :    y     :     z     :     x+y+z
  ?    : 3x       :   2y     :     1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
       333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 10:36 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection  or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John  : Martin :      Sum
   x   :    y     :     z     :     x+y+z
  ?    : 3x       :   2y     :     1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
       333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios
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Re: Math Topic

Post by Chuck Norris on Sun Jan 29, 2017 10:39 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection  or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John  : Martin :      Sum
   x   :    y     :     z     :     x+y+z
  ?    : 3x       :   2y     :     1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
       333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.
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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 10:41 pm

[You must be registered and logged in to see this link.] wrote:
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[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection  or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John  : Martin :      Sum
   x   :    y     :     z     :     x+y+z
  ?    : 3x       :   2y     :     1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
       333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.
ok :v i will concentrate next time :v
we will wait to another one solve it
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Re: Math Topic

Post by Chuck Norris on Sun Jan 29, 2017 10:43 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection  or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John  : Martin :      Sum
   x   :    y     :     z     :     x+y+z
  ?    : 3x       :   2y     :     1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
       333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.
ok :v i will concentrate next time :v
we will wait to another one solve it

You go ahead and try if you want to. a hint express all Money in x. you only need one variable. I have to go to bed now so cya.
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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 10:55 pm

no man i will give up Sad
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 10:58 pm

Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

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Re: Math Topic

Post by MaSoN^ on Sun Jan 29, 2017 11:05 pm

Error 404 - Math not found.

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[You must be registered and logged in to see this link.] wrote:lol did zeyad applied for KF? lololol [KF]Zeyad_Retard :3

[You must be registered and logged in to see this link.] wrote:UF.KiDDo is better than Toretto

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Re: Math Topic

Post by Lahhami^ on Sun Jan 29, 2017 11:09 pm

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Hint : i dont mean "angle" ----> angel lol
btw its not easy .
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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 11:14 pm

[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck = 25 , y = 24-(z+chuck )
zeyad +chuck + azbeee = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee
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Re: Math Topic

Post by =SdS=KrlozZ... on Sun Jan 29, 2017 11:36 pm

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee  = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck  = 25 ,   y = 24-(z+chuck )
zeyad +chuck  + azbeee  = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee

Come on xDD its a simple problem
Just guess it

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Re: Math Topic

Post by Zeyad_Ahmed on Sun Jan 29, 2017 11:42 pm

[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .
it looks hard but it easy it took me 5 minutes to solve lol :v
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Done
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Re: Math Topic

Post by [EK]Arnold^ on Mon Jan 30, 2017 3:19 am

Keep calm because maths teacher is here...

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Re: Math Topic

Post by Lahhami^ on Mon Jan 30, 2017 3:46 am

[You must be registered and logged in to see this link.] wrote:
[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .
it looks hard but it easy it took me 5 minutes to solve lol :v
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Done
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wrong , use trigonometry rules  xD
Hint :  use this  [You must be registered and logged in to see this image.]
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Re: Math Topic

Post by =SdS=KrlozZ... on Mon Jan 30, 2017 6:02 am

[You must be registered and logged in to see this link.] wrote:Keep calm because maths teacher is here...

Jaja puto :v

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Re: Math Topic

Post by Lahhami^ on Mon Jan 30, 2017 6:20 am

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Keep calm because maths teacher is here...

Jaja puto :v
puto = ridiculous , am i right ?
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Re: Math Topic

Post by Chuck Norris on Mon Jan 30, 2017 6:23 am

[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee  = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck  = 25 ,   y = 24-(z+chuck )
zeyad +chuck  + azbeee  = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee

Come on xDD its a simple problem
Just guess it

You can guess on Everything, but if you don't know how to actually solve something like that, guessing won't help in the long run.
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Re: Math Topic

Post by PeTer on Mon Jan 30, 2017 7:12 am

LOL. Many teacher in here
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Re: Math Topic

Post by =SdS=KrlozZ... on Mon Jan 30, 2017 7:28 am

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.


Well many forms to do it maybe, but there should be just 1 correct solution.

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Re: Math Topic

Post by Chuck Norris on Mon Jan 30, 2017 8:25 am

[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:
[You must be registered and logged in to see this link.] wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.


Well many forms to do it maybe, but there should be just 1 correct solution.

3 equations and 4 unknowns, that doesn't have 1 solution. The question mark, zeyad, azbee and Chuck is unknown.
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Re: Math Topic

Post by =SdS=KrlozZ... on Mon Jan 30, 2017 9:14 am

Zeyad = 15
Chuck = 10
Azbee = 5

Razz then it look like that

15 + 15 + 10 = 40
5 + 10 + 10 = 25
10 + 15 + 5 = 30

Razz

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Re: Math Topic

Post by Zeyad_Ahmed on Mon Jan 30, 2017 10:13 am

[EK]KillerLaham wrote:
[You must be registered and logged in to see this link.] wrote:
[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .
it looks hard but it easy it took me 5 minutes to solve lol :v
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Done
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wrong , use trigonometry rules  xD
Hint :  use this  [You must be registered and logged in to see this image.]
Sorry xD
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Re: Math Topic

Post by Lahhami^ on Mon Jan 30, 2017 10:24 am

[You must be registered and logged in to see this link.] wrote:[You must be registered and logged in to see this image.][/url]
Sorry xD
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srry to tell you that but , its also wrong xD Rolling Eyes
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Re: Math Topic

Post by =SdS=KrlozZ... on Mon Jan 30, 2017 10:33 am

Well e.e

0,1,1,2

3,?,8,?

:p

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Re: Math Topic

Post by =KF=dev1ce on Mon Jan 30, 2017 5:17 pm

0 Divided by 0 + 1 = ?
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Re: Math Topic

Post by =VO=judesharp(L) on Mon Jan 30, 2017 5:58 pm

Cold wrote:0 Divided by 0 + 1 = ?

The answer is 0 as 0/0+1=0/1=0

Here my question : sin theta+alpha = a and sin theta+beta=b , then prove that cos2alpha-beta-4ab cos alpha-beta= 1-2a square- 2b square
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Re: Math Topic

Post by Zeyad_Ahmed on Mon Jan 30, 2017 6:46 pm

[You must be registered and logged in to see this link.] wrote:
Cold wrote:0 Divided by 0 + 1 = ?

The answer is 0 as 0/0+1=0/1=0

Here my question : sin theta+alpha = a and sin theta+beta=b , then prove that cos2alpha-beta-4ab cos alpha-beta= 1-2a square- 2b square
First :v
Second According to the unknown value of Sin and the cos then we dont know what it refer to :v are you sure that you have the answer for it?
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